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135=x^2-6x
We move all terms to the left:
135-(x^2-6x)=0
We get rid of parentheses
-x^2+6x+135=0
We add all the numbers together, and all the variables
-1x^2+6x+135=0
a = -1; b = 6; c = +135;
Δ = b2-4ac
Δ = 62-4·(-1)·135
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-24}{2*-1}=\frac{-30}{-2} =+15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+24}{2*-1}=\frac{18}{-2} =-9 $
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